This is the key to the math trick. It is algebra, so if you are 11 or younger, consult with an older sibling or adult to figure it out :÷).
1. The "think of a number" step is represented by the variable "x". x is the number you thought of throughout this key.
2. When you add 2, that comes to, of course, x+2, or "the number you thought of plus two."
3. When you multiply by 3, you multiply the whole problem by 3. It would then look like this:
x(3)+2(3) or 3x+6. That is, "the number you thought of times 3 plus 6."
4. When you subtract 5, the problem becomes 3x+6-5 or 3x+1.
5. Then when you add 8, you are simply doing the same thing as in step two, with a different number.
The problem becomes: 3x+1+8 or 3x+9.
6. When you divide by 3, you are dividing the whole problem by 3, thus undoing the effects of step 3.
The problem then looks like this: 3x+9(÷3) or x+3
7. The subtract 1 step is merely removing 1 so that you can get 2 as your answer. The problem looks like this: x+3-1 or x+2
8. The "subtract the number you first thought of" step removes x, or, "the number you first thought of". You are then left with 2.
'Phew! That's a lot of typing! I hope you now understand.
Adios,
Haydn
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